HOW TO SUBSCRIBE FOR_2019 NECO MATHEMATICS EXPO
YOU HAVE NO REASON TO DAONT WHEN I TELL YOU THAT MATHS ANSWERS WILL BE SEND TO OUR SUBSCRIBERS AT MIDNIGHT COS THOSE SUBSCRIBE FOR ENGLISH CAN TESTIFY HOW EARLY THE ANSWERS CAME. SUBSCRIBE FOR UR MATHEMATICS EXPO NOW
NECO June 2018 Essay/Obj – General Mathematics Expo Answer is out
CLICK HERE TO TO VIEW THE ANSWERS
NECO June 2018 Essay/Obj – General Mathematics Expo Answer is out
CLICK HERE TO TO VIEW THE ANSWERS
=======================================
DIRECT MOBILE (SMS) #1000 Airtel Card
WHATSAPP ANSWERS: #800
PASSWORD LINK: #500
====================================
Click on the link below to whatsapp me
https://wa.me/2348109654692?text=Hello%20I'm%20interested%20in%20ur%20NECO%202019%20Exam%20Runz
Click on the link below to whatsapp me
https://wa.me/2348109654692?text=Hello%20I'm%20interested%20in%20ur%20NECO%202019%20Exam%20Runz
Forward Your Airtel PIN, Subject Name, Phone number to: 08109654692 via Text Message (SMS) or here on WhatsApp
*Note Mathematics OBJ and Essay will be send to 6hrs b4 exam time*
TEXT MESSAGE: Sending you NECO 2019 Mathematics Answers on your phone as Text Message will cost you N1000 MTN CARD.
WHATSAPP MESSAGE: Sending you 2019 NECO Mathematics Questions and Answers to you on WhatsApp will cost you N800 MTN CARD. Add 09035656264 for your answers.
PIN LINK ONLINE: We’ll post the 2019 Neco Ssce Mathematics solutions on our answers portal and lock the page with a pin. PIN LINKcost N800 MTN CARD for each subject.
Previous 2018 Neco Mathematics Answers
Monday 4th June 2018
MATHEMATICS OBJ:
110 CDAAEABAEC
1120 AEDDCDCDCC
2130 CEBDEDCBBC
3140 CBEEECBDCC
4150 DBCBCDDBCA
5160 BCBDCDCCEC
MATHEMATICS OBJ:
110 CDAAEABAEC
1120 AEDDCDCDCC
2130 CEBDEDCBBC
3140 CBEEECBDCC
4150 DBCBCDDBCA
5160 BCBDCDCCEC
10a)
Obtuse <BOD + Reflex<BOD = 360degrees (angle at a point)
105 + reflex<BOD = 360degrees
Reflex <BOD= 360  105
=255°
Now 2w = reflex<BOD(angle at centre = twice angle at circumference)
2w =255°
W = 255/2 =127.5°
Also 2x = obtuse<BOD(angle at centre = twice angle at circumference)
2x = 105°
X = 105/2 = 52.5°
Now EDF = y(base angles of an isosceles triangle)
BED=X=52.5°(angles in the same segment)
EFD+EDF=BED (sum of interior angles of a triangle equal exterior angle)
Y+y = 52.5°
2y = 52.5°
Y = 52.5°/2
=26.25°
(10b)
Draw the diagram
Opp/adj = TanR
TB/BR = TanR
100/BR = Tan60°
BR = 100/tan60
BR = 100√3
BR = 100√3 * √3/√3
=100√3/3m OR 57.7m
11a)
x+y/2 =11
x+y= 11*2
x+y= 22 (1)
xy= 4 (11)
x+y = 22(1)

xy= 4(11)
____
2y = 18
y= 18/2
y=9
Substitute y=9 in equ 1
x+9=22
x=229
x=13
x=13, y=9
x+y= 13+9= 22
Sum of the two number
(11b)
(6x + 3) dx
(6x + 3)dx
(6x +3)^6  (6x + 3)^1
(6 x + 3)^5
(7776x^5 + 243)
38,880x/6 + 243
6480 x^6 + 243x
9(720x^6 + 27x)
(11c)
y = x² + 5x  3 (x = 2)
y = 2² + 5(2)  3
y = 4 + 10  3
y = 14  3
y = 11
Gradient of the curve = 11
Correct 1a)
Log 10(2010)log10(+3)=log105
(2010/+3)=log10 =5
2010/+3=5
5(+3)=2010
5+15=2010
15+10=205
25=15*
=25/15
*=5/3=1 2/3
1b)
Discount percent =15%
Discount amount =#600
Actual amount paid on the article =?
Original amount on the article =
15%=#600
15/100 =600
15=600100
15*=60000
*=60000/15
*=#4,000
Therefore actual amount paid on the article
=#4,000#600
=#3,400
Actual amount paid on the article =#3,400
No 4(i)
length of Arc of the sector
Titter= 72?, r = 14cm
L= titter / 360 x 2 pie r
==> L= 72/360 x 2 x 22/7 x 14
=44352/2520 = 17.6cm
(ii) perimeter of the sector
Perimeter = titter/360 x 2 pie r + 2r = 17.6 +(2×14) =17.6+28= 45.6cm
iii) Area of the sector
Area = Titter/360 x pie r? =
72/360 x 22/7 x (14)? = 72 x 22 x 196/2520
Area= 310464/2520 = 123.2cm?
Obtuse <BOD + Reflex<BOD = 360degrees (angle at a point)
105 + reflex<BOD = 360degrees
Reflex <BOD= 360  105
=255°
Now 2w = reflex<BOD(angle at centre = twice angle at circumference)
2w =255°
W = 255/2 =127.5°
Also 2x = obtuse<BOD(angle at centre = twice angle at circumference)
2x = 105°
X = 105/2 = 52.5°
Now EDF = y(base angles of an isosceles triangle)
BED=X=52.5°(angles in the same segment)
EFD+EDF=BED (sum of interior angles of a triangle equal exterior angle)
Y+y = 52.5°
2y = 52.5°
Y = 52.5°/2
=26.25°
(10b)
Draw the diagram
Opp/adj = TanR
TB/BR = TanR
100/BR = Tan60°
BR = 100/tan60
BR = 100√3
BR = 100√3 * √3/√3
=100√3/3m OR 57.7m
11a)
x+y/2 =11
x+y= 11*2
x+y= 22 (1)
xy= 4 (11)
x+y = 22(1)

xy= 4(11)
____
2y = 18
y= 18/2
y=9
Substitute y=9 in equ 1
x+9=22
x=229
x=13
x=13, y=9
x+y= 13+9= 22
Sum of the two number
(11b)
(6x + 3) dx
(6x + 3)dx
(6x +3)^6  (6x + 3)^1
(6 x + 3)^5
(7776x^5 + 243)
38,880x/6 + 243
6480 x^6 + 243x
9(720x^6 + 27x)
(11c)
y = x² + 5x  3 (x = 2)
y = 2² + 5(2)  3
y = 4 + 10  3
y = 14  3
y = 11
Gradient of the curve = 11
Correct 1a)
Log 10(2010)log10(+3)=log105
(2010/+3)=log10 =5
2010/+3=5
5(+3)=2010
5+15=2010
15+10=205
25=15*
=25/15
*=5/3=1 2/3
1b)
Discount percent =15%
Discount amount =#600
Actual amount paid on the article =?
Original amount on the article =
15%=#600
15/100 =600
15=600100
15*=60000
*=60000/15
*=#4,000
Therefore actual amount paid on the article
=#4,000#600
=#3,400
Actual amount paid on the article =#3,400
No 4(i)
length of Arc of the sector
Titter= 72?, r = 14cm
L= titter / 360 x 2 pie r
==> L= 72/360 x 2 x 22/7 x 14
=44352/2520 = 17.6cm
(ii) perimeter of the sector
Perimeter = titter/360 x 2 pie r + 2r = 17.6 +(2×14) =17.6+28= 45.6cm
iii) Area of the sector
Area = Titter/360 x pie r? =
72/360 x 22/7 x (14)? = 72 x 22 x 196/2520
Area= 310464/2520 = 123.2cm?
How to Send Payment for 2019 NECO Mathematics Runs.
Send the below details:
 Your MTN CARD
 Your Subject Name
 Your Phone Number to 08109654692
Example on how to send your details to us: MTN CARD N400: 57575858588585/ Subject: Mathematics / Phone Number 090123456789
PLEASE NOTE:
– MTN recharge card only.
– Do not call us just text message, we will reply to your message immediately.
– If you’re a Teacher WhatsApp Is the best Package to subscribe to because questions and answers are written on paper, snapped and uploaded to the WhatsApp group.
– PIN Online Link Subscribers Will Get Their Answers on:mydport.com.ng/pin/
– WhatsApp Subscribers Should Add Studentbaze On: 09035656264
– Do not stay here waiting for free answers to fall from sky because we won’t post answers for free like we did last year and also questions and answers doesn’t fall from sky like the leaves falling from trees. GOOD LUCK!
0 Comments